Answer:
Total resistance = 0.92Ω
Explanation:
For parallel connected resistors we have effective resistance
[tex]\frac{1}{R_{eff}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+.....[/tex]
Here parallel circuit made up of resistances of 2Ω, 3Ω, and 4Ω.
That is
R₁ = 2Ω
R₂ = 3Ω
R₃ = 4Ω
Substituting
[tex]\frac{1}{R_{eff}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}\\\\\frac{1}{R_{eff}}=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\\\\\frac{1}{R_{eff}}=\frac{6+4+3}{12}\\\\R_{eff}=\frac{12}{13}=0.92ohm[/tex]
Total resistance = 0.92Ω
