After Callie obtained her original results, she wanted to dig deeper. She determined that the germinating corn seed had utilized 100 molecules of glucose in the first few seconds that she performed the experiment. If these data are accurate, how many carbon dioxide molecules would Callie expect to have been released as a waste during this same amount of time? Explain how you arrived at your answer. The formula for cellular respiration is shown below.
C6H12O6 + 6O2 → 6CO2 + 6H2O + energy

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yisausakiru yisausakiru · Answer 1 · 2020-01-31T06:56:17+01:00

Answer: 600 molecules of CO2

Explanation:

C6H12O6 + 6O2 → 6CO2 + 6H2O + energy

From the above balanced equation, 1 mole of glucose produces 6 moles of CO2.

Mathematically,

1 mole of C6H12O6 = 6 moles of CO2

Let,

100 moles of C6H12O6 = x mole of CO2

By simply cross multiply,

x mole of CO2 = (6 ×100)/1 mole

x mole of CO2 = 600 mole

Callie should expect 600 molecules of carbon dioxide to have been released as a waste during this same amount of time.

throwdolbeau throwdolbeau · Answer 2 · 2022-02-17T13:48:32+01:00

Callie should expect 600 molecules of carbon dioxide.

[tex]C_6H_{12}O_6 + 6O_2 ----> 6CO_2 + 6H_2O + \text {energy}[/tex]

From the reaction, 1 mole of glucose produces 6 moles of carbon dioxide.

1 mole of [tex]C_6H_{12}O_6[/tex] = 6 moles of [tex]CO_2[/tex]

Let,

100 moles of [tex]C_6H_{12}O_6[/tex] = x mole of [tex]CO_2[/tex]

By simply cross multiply,

x mole of [tex]CO_2[/tex] = [tex]\frac{(6*100)}{1} =600[/tex] mole

Callie should expect 600 molecules of carbon dioxide to have been released as a waste during this same amount of time.

Find more information about Cellular respiration here:

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