Answer:
Work done,W = -13.875 J
Explanation:
It is given that,
Mass of the ball, m = 0.25 kg
Initial speed of the ball, u = 20 m/s
Final speed of the ball, v = 17 m/s
Let W is the work done by the ball during its flight. Using the work energy theorem, the work done is equal to the change in kinetic energy of the ball. It is given by :
[tex]W=\dfrac{1}{2}m(v^2-u^2)[/tex]
[tex]W=\dfrac{1}{2}\times 0.25\ kg\times ((17\ m/s)^2-(20\ m/s)^2)[/tex]
W = -13.875 J
So, the work done by the air resistance on the ball during its flight is (-13.875 J). Hence, this is the required solution.