Respuesta :
Answer:
P = [tex]\frac{3C1 * 4C1}{12C2}[/tex]
Step-by-step explanation:
Number of art electives = 3
Number of history electives = 4
Number of computer electives = 5
Total number of electives = 12
The number of ways of selecting 1 art elective = [tex]3C1[/tex]
Number of ways of selecting 1 history elective = [tex]4C1[/tex]
Number of ways of selecting 2 electives from 12 electives = [tex]12C2[/tex]
Probability that a student chooses an art elective and a history elective
P = [tex]\frac{3C1 * 4C1}{12C2}[/tex]