Answer:
magnification = - 30
overall magnification = -240
Explanation:
given data
Focal length of microscope objective f = 0.150 cm
Object distance from microscope objective do = 0.155 cm
magnification by eyepiece = 8 ×
to find out
What magnification is produced and overall magnification
solution
we consider here Image distance from microscope objective is = di
so that
Magnification produced by objective will be = - [tex]\frac{di}{do}[/tex]
so we find here di by given equation that is
[tex]\frac{1}{do} +\frac{1}{di} = \frac{1}{f}[/tex] ..................1
[tex]\frac{1}{di} = \frac{1}{0.150} - \frac{1}{0.155}[/tex]
di = 4.65 cm
so that magnification by object will be
magnification = - [tex]\frac{di}{do}[/tex]
magnification = - [tex]\frac{4.65}{0.155}[/tex]
magnification = - 30
and
overall magnification will be
overall magnification = magnification by objective × magnification by eyepiece ........................2
overall magnification = -30 × 8
overall magnification = -240
