An iron nail is driven into a block of ice by a single blow of a hammer. The hammerhead has a mass of 0.5 kg and an initial speed of 3.2 m/s. Nail and hammer are at rest after the blow. How much ice melts? Assume the temperature of both the ice and the nail is 0◦C before and after. The heat of fusion of ice is 80 cal/g. Answer in units of g.

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Answer:

The ice melts mass is:

[tex]m_g=7.6x10^{-3} g[/tex]

Explanation:

Kinetic Energy  

[tex]K_E = 1/2*m*v^2[/tex]

[tex]K_E = 1/2*0.5kg*(3.2m/s)^2[/tex]

[tex]K_E=2.56 kg*m^2/s^2[/tex]

Heat gained by ice= mass(g) x 80 cal

( 1 cal = 4.184 *10^7er or g cm^2/ sec^2)

Assuming no loss in heat,  in the motion so both continue with temperature 0~C

To find so the mass (gm) of ice melted

[tex]m_g= 1/2 *(0.5*1000)*(3.2m/s)^2* 100*100 / (80*4.184*10^7)[/tex]

[tex]m_g=7.6x10^{-3} g[/tex]

Based on the conservation of heat energy, the mass of ice that melts is 0.0076 g

What is the energy generated by the hammerhead?

The energy generated by the hammerhead is in the form of kinetic energy.

The kinetic energy generated is calculated using the formula below:

[tex]K_E = \frac{1}{2} mv^{2}[/tex]

[tex]K_E = 1/2*0.5kg*(3.2m/s)^2[/tex]

[tex]K_E=2.56 J[/tex]

Heat gained by ice = mass x heat of fusion

1 cal = 4.184

80 cal = 334.72 J/g

Heat gained by ice = m × 334.72 J/g

Assuming no loss in heat;

Energy of hammerhead = energy used in melting uce

2.56 J = m × 334.72

m= 2.56/334.72

m = 0.0076 g

Therefore, mass of ice melted is 0.0076 g

Learn more about heat of fusion at: https://brainly.com/question/2426950