Answer: 90% confidence interval would be [tex](-0.2483,-0.0717)[/tex]
Step-by-step explanation:
Since we have given that
n₁ = 50
Number of metal tagged penguins survived = 10
So, [tex]p_m=\dfrac{10}{50}=0.2[/tex]
n₂ = 50
Number of electronic tagged penguins = 18
So, [tex]p_e=\dfrac{18}{50}=0.36[/tex]
So, at 90% confidence interval, z = 1.28
So, interval would be
[tex](p_m-p_e)\pm z\sqrt{\dfrac{p_m(1-p_m)}{n}+\dfrac{p_e(1-p_e)}{n}}\\\\=(0.2-0.36)\pm 1.28\sqrt{\dfrac{0.2\times 0.8}{50}+\dfrac{0.36\times 0.64}{50}}\\\\=-0.16\pm 0.0883\\\\=(-0.16-0.0883,-0.16+0.0883)\\\\=(-0.2483,-0.0717)[/tex]
Hence, 90% confidence interval would be
[tex](-0.2483,-0.0717)[/tex]