Answer:
a) τ= 2.59 MPa
b)y=28.4 x 10⁻⁵ cm
Explanation:
Given that
L= 3.3 cm
d= 7 cm
m= 1000 kg
G= 3 x 10¹⁰ Pa
Force due to load 1000 kg
P = m g= 1000 x 10 N
P = 10000 N
Area A
[tex]A=\dfrac{\pi}{4}d^2[/tex]
[tex]A=\dfrac{\pi}{4}\times 70^2\ mm^2[/tex]
A=3848.45 mm²
The shear stress τ
[tex]\tau=\dfrac{P}{A}[/tex]
[tex]\tau=\dfrac{10000}{3848.45}\ MPa[/tex]
τ= 2.59 MPa
Lets take vertical deflection is y
We know that
τ = G Φ
For small deflection
[tex]\phi=\dfrac{y}{L}[/tex]
So
τ L = G y
[tex]y=\dfrac{\tau L}{G}[/tex]
[tex]y=\dfrac{2.59\times 3.3}{3\times 10000}[/tex]
y=0.000284 cm
y=28.4 x 10⁻⁵ cm
