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Following the procedure, a student recorded the initial volume of NaOH in his buret as 2.82 mL. He then titrated a 15.00 mL sample of 0.1027 M HCl until a persistent pale pink appeared. He recorded the final volume of NaOH in his buret as 17 mL. What is the concentration (M) of his NaOH solution?

Respuesta :

Answer:

The concentration of this NaOH solution was 0.104 M

Explanation:

Step 1: Data given

Initial volume of NaOH = 2.82 mL = 0.00282 L

The sample is titrated with 15.00 mL of 0.1027 M HCl

Final volume NaOH = 17 mL = 0.017 L

Step 2:  Calculate change in volumes

17 mL - 2.82 mL = 14.18 mL = 0.01418 L

Step 3: Calculate the concentration of the NaOH

C1*V1 = C2*V2

⇒ with C1 = the initial concentration = TO BE DETERMINED

⇒ with V1 = the initial volume =  0.0148 L

⇒ with C2 = the final concentration = 0.1027

⇒ with V2 = the final volume = 0.015 L

C1 = (0.1027*0.015) /0.0148

C1 = 0.104 M

The concentration of this NaOH solution was 0.104 M

samueladesida43

The concentration (M) of the students NaOH solution is 0.1086M

HOW TO CALCULATE MOLARITY:

  • The concentration of a solution in a titration experiment can be calculated by using the formula below:

CaVa = CbVb

Where;

  1. Ca = acid concentration
  2. Va = acid volume
  3. Cb = base concentration
  4. Vb = base volume

  • The volume of NaOH used in this experiment must first be calculated by finding the change as follows: 17mL - 2.82mL = 14.18mL.

  • Using the following formula as follows:

0.1027 × 15 = Cb × 14.18

1.5405 = 14.18Cb

Cb = 0.1086M

Therefore, the concentration (M) of the students NaOH solution is 0.1086M.

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