Answer:
we can see that block is accelerating with more acceleration and hence it will reach the bottom first
Explanation:
As we know that cylinder is rolling without slipping on the inclined plane
So the acceleration of the cylinder is given as
[tex]a = \frac{gsin\theta}{1 + \frac{k^2}{R^2}}[/tex]
so we know that
[tex]\frac{k^2}{R^2} = \frac{1}{2}[/tex]
so we have
[tex]a = \frac{gsin\theta}{1 + \frac{1}{2}}[/tex]
[tex]a = \frac{2}{3}g sin\theta[/tex]
Now the acceleration of block which is slipping on the floor
[tex]a = g sin\theta[/tex]
so here we can see that block is accelerating with more acceleration and hence it will reach the bottom first