Step-by-step explanation:
Let [tex]m_{1}[/tex] be the slope of the given line and [tex]m_{2}[/tex] be the slope of the new line.
given,[tex]m_{1}=\frac{1}{2}[/tex].
Since,the given line and the new line are perpendicular,
[tex]m_{1}m_{2}=-1[/tex]
So,[tex]m_{2}=-2[/tex]
It is given that the new line passes through x-intercept of the given line.
The x-intercept of the given line is [tex](-3,0)[/tex]
The equation of the line passing through [tex](x_{1},y_{1})[/tex] and slope [tex]m[/tex] is [tex]y-y_{1}=m(x-x_{1})[/tex]
So,the line is [tex]y-0=-2(x+3)[/tex]
[tex]y=-2x-6[/tex]