To develop the problem it is necessary to solve the exercise through the equations of balance of force, specifically with those of Torque.
The torque is given by the function
[tex]\tau = F*d[/tex]
Where,
F= Force
d= Distance
Force is defined by second Newton's law as
F = mg
By balance the total torque would be given by
[tex]\tau = m_1g*d_1-m_2g*d_2[/tex]
[tex]\tau = (1kg)(9.8m/s^2)(0.4m)-(0.5)(9.8)(0.6)[/tex]
[tex]\tau = 1Nm[/tex]
Therefore the correct answer is 1Nm.
The magnitude of the net torque on the meterstick about the fulcrum is most nearly 1 N middot m. hence, option (A) is correct.
Given data:
The distance between the fulcrum and mark is, d = 0.4 m/
The mass hung with fulcrum is, m = 1 kg.
Value of another mass is, m' = 0.5 kg.
The distance kept is, d' = 1.0 m.
The problem is solved through the equations of balance of force, specifically with those of Torque. By balance the total torque would be given by,
[tex]\tau = Fd-F'(d'-d)\\\\\tau = mgd-m'g(d'-d)[/tex]
Here, g is the gravitational acceleration.
Solving as,
[tex]\tau = (1 \times 9.8 \times 0.4)-0.5 \times 9.8 (1-0.4)\\\\\tau = 1 \;\rm N[/tex]
Thus, we can conclude that the magnitude of the net torque on the meterstick about the fulcrum is most nearly 1 N middot m. hence, option (A) is correct.
Learn more about the torque here:
https://brainly.com/question/19247046
