Explanation:
The reaction equation will be as follows.
[tex]Na^{+} + e^{-} \rightarrow Na(s)[/tex]
Hence, moles of Na = moles of electron used
Therefore, calculate the number of moles of sodium as follows.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{4500 g}{23 g/mol}[/tex] (as 1 kg = 1000 g)
= 195.65 mol
As, Q = [tex]n \times F[/tex] where F = Faraday's constant
= [tex]195.65 mol \times 96500 C[/tex]
= [tex]1.88 \times 10^{7}[/tex] mol C
Relation between electrical energy and Q is as follows.
E = [tex]Q \times V[/tex]
Hence, putting the given values into the above formula and then calculate the value of electricity as follows.
E = [tex]Q \times V[/tex]
= [tex]1.88 \times 10^{7} \times 5[/tex]
= [tex]9.4 \times 10^{7} J[/tex]
As 1 J = [tex]2.77 \times 10^{-7}[/tex] kWh
Hence, [tex]\frac{9.4 \times 10^{7}}{2.77 \times 10^{-7}}[/tex] kWh
= 3.39 kWh
Thus, we can conclude that 3.39 kilowatt-hours of electricity is required in the given situation.