For this case we have that by definition, the equation of a line in the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: Is the slope
b: Is the cut-off point with the y axis
According to the data of the statement we have two points through which the line passes:
[tex](x_ {1}, y_ {1}): (0,7)[/tex](The cut-off point "b" is 7)
[tex](x_ {2}, y_ {2}): (3, -2)[/tex]
We found the slope:
[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-2-7} {3-0} = \frac {-9} {3} = -3[/tex]
Thus, the equation is of the form:
[tex]y = -3x + b[/tex]
We know that[tex]b = 7[/tex]
Finally, the equation is:
[tex]y = -3x + 7[/tex]
So, Sarita is not right.
Answer:
[tex]y = -3x + 7[/tex]
