Respuesta :
Answer:
Enthalpy change when 10.0 moles of aluminium reacts with stoichiometrically equivalent ferric oxide is [tex]-4.25\times 10^{3} kJ[/tex].
Explanation:
[tex]2Al(s)+Fe_2O_3(s)\rightarrow 2Fe(s)+Al_2O_3(s),\Delta H^o_{rxn}=-850 kJ[/tex]
Energy change of the reaction when 2 mole of aluminium reacts with 1 mol of ferric oxide : [tex]\Delta H^o_{rxn}=-850 kJ[/tex]
Energy change of the reaction when 1 mole of aluminium reacts :
[tex]\frac{\Delta H^o_{rxn}}{2}=\frac{-850 kJ}{2}=-425 kJ[/tex]
Enthalpy change when 10.0 moles of aluminium reacts with stoichiometrically equivalent ferric oxide:
[tex]-425 kJ\times 10.0 =-4250.0 kJ=-4.25\times 10^{3} kJ[/tex]
