Respuesta :
Answer:
Explanation:
It is given that,
Mass of the loop, m = 10 g = 0.01 kg
Resistance of the loop, R = 0.02 ohms
Dimension of square loop, 7 cm × 7 cm
Area of the loop, [tex]A=49\ cm^2=49\times 10^{-4}\ m^2[/tex]
At time t = 0 s, the magnetic field increases from 0 to 1 T in 0.01 s
(a) Due to change in magnetic field, an emf is induced in the loop. Using the formula for induced emf as :
[tex]\epsilon=A\dfrac{dB}{dt}[/tex]
[tex]\epsilon=49\times 10^{-4}\times \dfrac{1}{0.01}[/tex]
[tex]\epsilon=0.49\ V[/tex]
Now using Ohm's law to find the induced current in the loop. It is given by :
[tex]I=\dfrac{\epsilon}{R}[/tex]
[tex]I=\dfrac{0.49}{0.02}[/tex]
I =24.5 A
(b) A magnetic force acting on the loop is given by :
[tex]F=iLB\ sin\theta[/tex]
[tex]F=i(l/2)B[/tex]
[tex]F=24.5\times (0.07/2)\times 1[/tex]
F = 0.8575
Since, [tex]F=\dfrac{mv}{t}[/tex]
[tex]\dfrac{mv}{t}=0.8575[/tex]
[tex]v=\dfrac{0.8575\times 0.01}{0.01}[/tex]
v = 0.8575 m/s
Hence, this is the require solution.
