Answer:
The work done by the force is 6μJ
Explanation:
Suppose, A 30 nC charge is moved from a point where V₁ = 130 V to a point where V₂ = -70 V.
We need to calculate the work done by the force
Using formula of work done
[tex]W=-q\Delta V[/tex]
Where, q = charge
[tex]\Delta V[/tex] =potential difference
Put the value into the formula
[tex]W=-30\times10^{-9}\times(-70-130)[/tex]
[tex]W=0.000006\ J[/tex]
[tex]W=6\times10^{-6}\ J[/tex]
[tex]W=6\ \mu J[/tex]
Hence, The work done by the force is 6μJ.
