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A car traveling along a straight road at 71 ft/sec accelerated to a speed of 79 ft/sec over a distance of 160 ft. What was the acceleration of the car, assuming it was constant? (Round your answer to two decimal places.)

Respuesta :

Answer:

Acceleration of car = 3.75 ft/s²

Explanation:

We have equation of motion v² = u² + 2as

Initial velocity, u = 71 ft/s

Final velocity, v = 79 ft/s

Displacement, s = 160 ft

Acceleration, a = ?

Substituting

              v² = u² + 2as

              79² = 71² + 2 x a x 160

               a = 3.75 ft/s²

Acceleration of car = 3.75 ft/s²

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