Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.
Solution:
Given that,
Total circulation of local newspaper in 2000 = 3250
Total circulation of local newspaper in 2001 = 3640
Total circulation of local newspaper in 2002 = 4100
Finding percent of increase in the newspaper’s circulation from 2000 to 2001:
[tex]\text { Percent increase from } 2000 \text { to } 2001=\frac{\text { change in circulation from 2001 - 2000 }}{\text { circulation in } 2000} \times 100[/tex]
[tex]\begin{array}{l}{=\frac{3640-3250}{3250} \times 100} \\\\ {=\frac{390}{3250} \times 100=12 \%}\end{array}[/tex]
Finding percent of increase in the newspaper’s circulation from 2001 to 2002:
[tex]\begin{array}{l}{\text { Percent increase from } 2001 \text { to } 2002=\frac{\text { change in circulation }}{\text {circulation in } 2001} \times 100} \\\\ {=\frac{4100-3640}{3640} \times 100} \\\\ {=\frac{460}{3640} \times 100=12.6 \%}\end{array}[/tex]
As we can see 12% < 12.6%
So period of 2001 to 2002 has higher increase percentage.
