Answer:
Step-by-step explanation:
Hello!
The FMA Company designed a new type of bowling ball and want to test if the new bowling average differs from the bowling average of the old model. Symbolically μ≠155
Sample:
n= 120 men bowling in scratch leagues
sample mean x[bar]= 170
variance δ²= 100
The hypothesis is:
H₀:μ=155
H₁:μ≠155
α: 0.05
The statistic to use for this hypothesis, assuming that the variable has a normal distribution.
Z= x[bar]-μ ≈ N(0;1)
δ/√n
The critical region for this test is two-tailed, this means you'll reject the null hypothesis to small or big values of the statistic.
[tex]Z_{\alpha/2}[/tex] = [tex]Z_{0.025}[/tex] = -1.96
[tex]Z_{1-\alpha/2}[/tex] = [tex]Z_{0.975}[/tex] = 1.96
You'll reject the null hypothesis to values of Z≤-1.96 or Z≥1.96.
Under the null Hypothesis the statistic value is:
Z= x[bar]-μ
δ/√n
Z= 170-155
10/√120
Z= 15/0.913 = 16.42
Decision: Reject the null Hypothesis.
I hope you have a SUPER day!