Answer:[tex]0.0393 kg-m^2/s[/tex]
Explanation:
Given
mass of stick [tex]m=135 gm[/tex]
angular speed of stick [tex]\omega =3.50 rad/s[/tex]
Length of stick [tex]L=1 m[/tex]
Moment of inertia of stick Perpendicular to the stick passing through the center is given by
[tex]I=\frac{mL^2}{12}[/tex]
[tex]I=\frac{0.135\times 1^2}{12}=0.01125 kg-m^2[/tex]
Angular Momentum is [tex]L=I\omega [/tex]
[tex]L=0.01125\times 3.5=0.0393 kg-m^2/s[/tex]
