Explanation:
Let [tex]f[/tex] be the time period of hammer.
Let [tex]r[/tex] be the length of the rope.
Let [tex]v[/tex] be the speed of hammer.
Given,
[tex]r=0.6m\\f=3sec^{-1}[/tex]
Since speed of hammer is the ratio of distance travelled in one cycle and frequency,
[tex]v=2\pi rf=2\pi \times0.6\times 3=11.3 ms^{-1}[/tex]
Let [tex]T[/tex] be the tension in rope.
Since the tension in the rope is balancing the centripetal force,
[tex]T=\frac{mv^{2}}{r}=\frac{0.1\times 11.3^{2}}{0.6}=21.3N[/tex]
