The slope of the ramp is [tex]\frac{7}{40}[/tex] if two beams are apart at 40 feet and at heights of 3.5 feet and 10.5 feet respectively.
Step-by-step explanation:
The two beams are 40 feet apart this is the horizontal distance.
As per the given question 3.5 feet beam is at initial point that is [tex]x_{1}=0[/tex] and beams are apart 40 feet that is [tex]x_{2}=40[/tex].
Vertical distance is the heights of the beam are [tex]\mathrm{y}_{1}=3.5[/tex] feet and other bean is [tex]\mathrm{y}_{2}=10.5[/tex]
To find the slope of the ramp we know that, slope is the ratio of the vertical change to the horizontal change.
[tex]\text { slope of the ramp }=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
Substitute the values [tex]x_{1}=0, x_{2}=40, y_{1}=3.5 \text { and } y_{2}=10.5[/tex] in the above formula.
[tex]\text { slope of the ramp }=\frac{10.5-3.5}{40-0}[/tex]
[tex]\text {slope of the ramp}=\frac{7}{40}[/tex]
Thus by using the slope formula we found that slope of the ramp for the given conditions is [tex]\frac{7}{40}[/tex].
Answer:
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Step-by-step explanation:
