Answer:
CH₅
Explanation:
This question may be lacking some information and in order to solve it, I will assume that the compound is a hydrocarbon, and therefore the percentages of carbon and hydrogen are:
C = 70.79 % H = 100 - 70.79 = 29.21 %
In 100 grams of compound wil have
70.79 g C
20.21 g H
Dividing by the atomic weights to get the mol of atoms:
C= 70.71 g/ 12 g/mol = 5.90 mol
H= 29.21 g/1 g/mol = 29.21 mol
Dividing by the 5.90 to get the proportions ,
C = 5.90/5.90 = 1
H= 29.21/5.90 = 4.95 rounding to 5,
the empirical formula is 1 atom of carbon per 5 of hydrogen
CH₅
