Respuesta :
Answer:
The test statistic is [tex]Z=\frac{\hat{p}-0.15}{\sqrt{0.15(0.85)/100}}[/tex] and the observed value 1.68
Step-by-step explanation:
We have a large sample size n = 100, the point estimate for the true proportion of overfilled bags p is given by [tex]\hat{p} = 21/100[/tex]. The test statistic is given by [tex]Z=\frac{\hat{p}-0.15}{\sqrt{0.15(0.85)/100}}[/tex] which is distributed as a standard normal variable approximately because we have a large sample. The observed value for the test statistic in this case is [tex]z=\frac{0.21-0.15}{\sqrt{0.15(0.85)/100}} = 1.68[/tex]
The test statistic from the information about the chips company will be 1.68.
How to compute the test statistics?
Firstly, the sample proportion will be = 21/100 = 0.21
The claimed proportion = 0.15
Significance level = 0.05
Standard deviation will be:
= [✓0.15 × ✓0.85 / ✓100]
= 0.036
Therefore, the test statistic will be:
= [(0.21) - 0.15] / 0.036
= 1.68
In conclusion, the test statistic is 1.68.
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