Answer:
The standard error of the mean = 5.14 mins
Step-by-step explanation:
Number of random sample (n) = 20
Mean(X) = 31.25 mins
Standard deviation (α) = 23.7 mins
Standard error of mean =
standard deviation / √sample size
= 23.7/√20
= 23.7/4.4721
= 5.14 mins