Answer:[tex]\dfrac{7}{13}[/tex]
Step-by-step explanation:
There are only two games basketball and baseball.
Any student who plays could play basketball or baseball.
Given that there are [tex]26[/tex] students in total.
Given that there are [tex]12[/tex] students who don't play any game at all.
So,there are [tex]26-12=14[/tex] students who play play some baseball or basketball.
[tex]Probability=\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}[/tex]
The required probability is [tex]\frac{14}{26}=\frac{7}{13}[/tex]