A 69 g particle is moving to the left at 25 m/s . How much net work must be done on the particle to cause it to move to the right at 31 m/s ? Express your answer to two significant figures and include the appropriate units.

Respuesta :

Answer:11.59 J

Explanation:

Given

mass of Particle [tex]m=69 gm[/tex]

Initially Particle moves towards left [tex]v_1=25 m/s[/tex]

Final velocity of Particle is towards Right [tex]v_2=31 m/s[/tex]

According to Work Energy theorem

Work done by all the Forces=change in Kinetic Energy

Work done by Force[tex]=\frac{mv_2^2}{2}-\frac{mv_1^2}{2}[/tex]

[tex]W=\frac{69\times 10^{-3}}{2}\left [ 31^-25^2\right ][/tex]

[tex]W=\frac{69\times 10^{-3}}{2}\left [ 961-625\right ][/tex]

[tex]W=11.59 J[/tex]