Answer:
Step-by-step explanation:
[tex]t=2\dfrac{2}{3}\ h=\dfrac{2\cdot3+2}{3}\ h=\dfrac{8}{3}\ h\\\\r=36\ mph\\\\\text{Substitute to}\ d=rt:\\\\d=36\!\!\!\!\!\diagup^{12}\ \dfrac{mi}{h\!\!\!\!\diagup}\cdot\dfrac{8}{3\!\!\!\!\diagup_1}\ h\!\!\!\!\diagup=(12\ mi)(8)=96\ mi[/tex]
