Answer:
9 units.
Step-by-step explanation:
Let ab and cd are the parallel sides of the given parallelogram.
Hence [tex]\frac{1}{2} (ab + cd)[/tex] is the mid segment of this trapezoid.
Now, coordinates of a, b, c and d are respectively (-11,3), (0,3), (-8,-2), and (-1,-2).
So, the length of ab = [tex]\sqrt{(-11 - 0)^{2} + (3 - 3)^{2}} = 11[/tex] units
And the length of cd = [tex]\sqrt{(-8 - (- 1))^{2} + (- 2 - ( - 2))^{2} } = 7[/tex] units
Therefore, the mid segment of this trapezoid is [tex]\frac{1}{2} (11 + 7) = 9[/tex] units. (Answer)
The length of a straight line connecting two points ([tex]x_{1}, y_{1}[/tex]) and ([tex]x_{2}, y_{2}[/tex]) is equal to
[tex]\sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2} }[/tex]