Answer:
Country A = 85, Country B = 29, Country C = 20
Step-by-step explanation:
A+B+C=134 ----- eq(1)
B=C+9 ------------ eq(2)
A=36+B+C ------ eq(3)
By substituting eq(2) in eq(3), we get:
A=36+C+9+C
A=2C+45 ------- eq(4)
Now substituting eq(2) & eq(4) in eq(1), we get
2C+45+C+9+C=134
4C+54=134
4C=134-54
4C=80
C=20
Now putting the value of C in eq(2),
B=20+9
B=29
Substituting the value of B & C in eq(1), we get:
A+29+20=134
A+49=134
A=134-49
A=85
Country A won 85 medals, Country B won 29 medals and Country C won 20 medals.
Let a represent the number of medals won by country A, b represent the medals won by country B and c represent the medals won by country C.
Since a total of 134 medals was won, hence:
a + b + c = 134 (1)
Country B won 9 more medals than country C. Hence:
b = c + 9
b - c = 9 (2)
Country A won 36 more medals than the total amount won by the other two. Hence:
a = b + c + 36
a - b - c = 36 (3)
Solving equations 1, 2 and 3 simultaneously gives:
a = 85, b = 29 and c = 20
Therefore Country A won 85 medals, Country B won 29 medals and Country C won 20 medals.
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