Answer:
[tex]\tan \angle A[/tex]= [tex]1.33[/tex]
[tex]\tan \angle B[/tex] = [tex]0.75[/tex]
Step-by-step explanation:
Given:
[tex]\triangle ABC[/tex] is a right triangle.
[tex]\angle ACB = 90\°[/tex]
To find:
[tex]\tan \angle A[/tex]
[tex]\tan \angle B[/tex]
We know that tangent of an angle is given by the ratio= [tex]\frac{Opposite\ side}{Adjacent\ side}[/tex]
The opposite side and adjacent side is taken with respect to the angle for which the tangent is to be found.
[tex]\tan \angle A[/tex]= [tex]\frac{BC}{AC}=\frac{4}{3}=1.33[/tex]
[tex]\tan \angle B[/tex]= [tex]\frac{AC}{BC}=\frac{3}{4}=0.75[/tex]
