Answer:
The length of the rectangle is 16 feet, the width of the rectangle is 8 feet.
Step-by-step explanation:
1. Let's check the information given to resolve the question:
Length of the rectangle = x
Width of the rectangle = x/2 ( half as long as the length)
Area of the rectangle = 128 square feet
2. Let's find the value of the length and the width
Area of the rectangle = Length of the rectangle * Width of the rectangle
128 = x * x/2
128 = x² /2 (x * x = x²)
256 = x² (Multiplying by 2 to both sides of the equation)
x² = 256
√x² = √ 256
x = 16
The length of the rectangle is 16 feet.
Width of the rectangle = x/2 = 16/2 = 8 feet.
The length of the rectangle is 16 feet, the width of the rectangle is 8 feet.
Answer:
The rectangle has length = 16 feet, width = 8 feet
Explanation:
Let the length be x, we are given that width is half as long as the length so we can say that width is equal to x/2
We are given the area to be = 128 square feet ,
and we know area = length x breadth
So area = [tex]x \times (\frac{x}{2})[/tex]
=> [tex]2\times 128 = x\times x[/tex]
=> 256 = [tex]x\times x[/tex]
=> x = 16 = length
and width =[tex]\frac{x}{2} = \frac{16}{2} = 8[/tex]
which are the required length and breadth of the rectangle
