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A car of mass 1000kg goes on a circular track with a diameter of 100m. The car moves at constant speed and makes 6 revolutions in 2 min.

The frequency is Hz

The period of the car is s

The speed of the car is m/s

Respuesta :

Answer:[tex]\dfrac{1}{20}[/tex][tex]seconds^{-1}[/tex],20[tex]seconds[/tex],15.7[tex]ms^{-1}[/tex]

Explanation:

Frequency is defined as the number of revolutions made the object in unit time.

Given that it takes [tex]2[/tex] minutes [tex]6[/tex] revolutions.

So,[tex]\frac{6}{2} =3[/tex] revolutions can be completed in [tex]1[/tex] minute.

So,[tex]\frac{3}{60} =\frac{1}{20}[/tex] revolutions can be completed in a second.

So,frequency is [tex]\frac{1}{20}[/tex]

Period of a object is the inverse of frequency.

Inverse of frequency [tex]\frac{1}{\frac{1}{20} }=20[/tex]

So,period is [tex]20seconds[/tex].

Speed of car is the given by the ratio of distance covered in one revolution to the time period.

Distance travelled in one period is [tex]\pi d[/tex] where [tex]d[/tex] is the diameter.

Given that [tex]d=100m[/tex]

So,distance travelled in one revolution [tex]\pi \times 100=315.15m[/tex]

Time period is [tex]20seconds[/tex].

Speed is [tex]\frac{314.15}{20}=15.7ms^{-1}[/tex]