Answer:
5.024 years
Explanation:
T1 = 1 year
r1 = 150 million km
r2 = 440 million km
let the period of asteroid orbit is T2.
Use Kepler's third law
T² ∝ r³
So,
[tex]\left ( \frac{T_{2}}{T_{1}} \right )^2=\left ( \frac{r_{2}}{r_{1}} \right )^3[/tex]
[tex]\left ( \frac{T_{2}}{1} \right )^2=\left ( \frac{440}{150} \right )^3[/tex]
T2 = 5.024 years
Thus, the period of the asteroid's orbit is 5.024 years.
