Answer:
779 g of chlorine would produce 7.3 moles of AlCl₃
Explanation:
Given data:
Mass of chlorine gas = 779 g
Number of moles of Aluminium chloride formed = ?
Solution:
Chemical equation:
2AlBr₃ + 3Cl₂ → 2AlCl₃ + 3Br₂
Number of moles of chlorine:
Number of moles = mass/ molar mass
Number of moles = 779 g/ 71 g/mol
Number of moles = 11 mol
Now we will compare the moles of chlorine with Aluminium chloride.
Cl₂ : AlCl₃
3 : 2
11 : 2/3×11 = 7.3 mol
779 g of chlorine would produce 7.3 moles of AlCl₃.
