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Two boxes (24 kg and 62 kg) are being pushed across a horizontal frictionless surface, as the drawing shows. The 36-N pushing force ModifyingAbove Upper P With right-arrow is horizontal and is applied to the 24-kg box, which in turn pushes against the 62-kg box. Find the magnitude of the force ModifyingAbove Upper F With right-arrow that the 24-kg box applies to the 62-kg box.

Respuesta :

Answer:

[tex]F = 26.04 N[/tex]

Explanation:

As we know that system of two boxes are moving on frictionless surface

So here if two boxes are considered as a system

then we have

[tex]F = (m_1 + m_2) a[/tex]

[tex]m_1 = 24 kg[/tex]

[tex]m_2 = 62 kg[/tex]

[tex]F = 36 N[/tex]

[tex]36 = (24 + 62) a[/tex]

[tex]a = 0.42 m/s^2[/tex]

Now since we know that both the boxes are moving together so force applied by first box on other box is given as

[tex]F = ma[/tex]

[tex]F = (62 \times 0.42)[/tex]

[tex]F = 26.04 N[/tex]

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