Answer:
[tex]v_f = 4.22 m/s[/tex]
Explanation:
As we know by energy conservation
initial total energy = final total energy
so we have
[tex]\frac{1}{2}mv^2 + \frac{1}{2}I\omega^2 = \frac{1}{2}mv_f^2 + \frac{1}{2}I\omega_f^2 + mgL sin\theta[/tex]
so we have
[tex]v = R \omega[/tex]
[tex]I = mR^2[/tex]
[tex]mv_i^2 = mv_f^2 + mgL sin\theta[/tex]
[tex]5.50^2 = v_f^2 + (9.81)(3) sin25[/tex]
[tex]30.25 - 12.43 = v_f^2[/tex]
[tex]v_f = 4.22 m/s[/tex]
