Answer:
[tex]\%\ Composition\ of\ phosphorus=20.00\ \%[/tex]
Explanation:
The molecular formula of the monohydrate formed = [tex]MgNH_4PO_4.H_2O[/tex]
The molecular mass of the monohydrate formed = [tex]Mass_{Mg}+Mass_{N}+6\times Mass_{H}+5\times Mass_O[/tex]
So, Mass = 24 + 14 + 6 × 1 + 5 × 16 = 155 g
Mass of phosphorus = 31 g
Thus,
[tex]\%\ Composition\ of\ phosphorus =\frac{Mass_{phosphorus}}{Total\ mass}\times 100[/tex]
[tex]\%\ Composition\ of\ phosphorus=\frac{31}{155}\times 100[/tex]
[tex]\%\ Composition\ of\ phosphorus=20.00\ \%[/tex]
