Answer:
Final speed of the rocket, [tex]\Delta v= 29.16\ m/s[/tex]
Explanation:
It is given that,
Impulse delivered by an engine, J = 3.5 kg-m/s
Mass of the rocket, m = 120 g = 0.12 kg
To find,
The final speed of the rocket
Solution,
We know that the impulse is equal to the product of mass and velocity o it is equivalent to the change in momentum of an object.
[tex]J=\Delta P=m\times \Delta v[/tex]
[tex]\Delta v=\dfrac{J}{m}[/tex]
[tex]\Delta v=\dfrac{3.5\ kg-m/s}{0.12\ kg}[/tex]
[tex]\Delta v= 29.16\ m/s[/tex]
So, the final speed of the rocket once the engine has fired is 29.16 m/s.