The mean is 0.0118 approximately. So option C is correct
Solution:
Given that , The probability of winning a certain lottery is [tex]\frac{1}{77076}[/tex] for people who play 908 times
We have to find the mean number of wins
[tex]\text { The probability of winning a lottery }=\frac{1}{77076}[/tex]
Assume that a procedure yields a binomial distribution with a trial repeated n times.
Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial.
[tex]n=908, \text { probability } \mathrm{p}=\frac{1}{77076}[/tex]
[tex]\text { Then, binomial mean }=n \times p[/tex]
[tex]\begin{array}{l}{\mu=908 \times \frac{1}{77076}} \\\\ {\mu=\frac{908}{77076}} \\\\ {\mu=0.01178}\end{array}[/tex]
Hence, the mean is 0.0118 approximately. So option C is correct.
