Respuesta :
Answer:[tex]5.293\times 10^{-24}N[/tex],[tex]3.303\times 10^{-5}NC^{-1}[/tex]
Explanation:
Let [tex]a[/tex] be the acceleration experienced by the electron.
Let [tex]F[/tex] be the electric force acting on the electron.
Let [tex]m[/tex] be the mass of electron.
Question 1:
Given,[tex]m=9.109\times 10^{-31}Kg[/tex]
[tex]a=5800\times 10^{3}ms^{-2}[/tex]
Force is the product of mass and acceleration.
So,[tex]F=ma=9.109\times 10^{-31}times 5800\times 10^{3}=529.32\times 10^{-26}=5.293\times 10^{-24} N[/tex]
Question 2:
Let [tex]E[/tex] be the electric field strength.
Strength of electric field is defined as the ratio of force experienced by a particle in electric field to the charge of the particle.
[tex]E=\frac{F}{e}[/tex]
[tex]E=\frac{5.293\times 10^{-24}}{1.602\times 10^{-19}}=3.303\times 10^{-5}NC^{-1}}[/tex]
1. The magnitude of the electric force acting on the electron is [tex]5.293 \times 10^{-24}N[/tex]
2. The magnitude of the electric field strength is [tex]3.303 \times 10^{-5}NC^{-1}[/tex]
Calculation of the magnitude:
1.
We know that
The force should be the product of mass & acceleration
Now
[tex]= 9.109 \times 10^{-31} kg \times 5800 \times 10^3\\\\= 5.293 \times 10^{-24}N[/tex]
2.
Here we assume E be the electric field strength. It is defined by considering the ratio of force experienced by a particle in the electric field with respect to the charge of the particle.
Now
[tex]= 5.293 \times 10^{-24}N \div 1.602 \times 10^{-19} C\\\\= 3.303 \times 10^{-5}NC^{-1}[/tex]
learn more about the magnitude here: https://brainly.com/question/14576767
