Objects 1 and 2 attract each other with a gravitational force of 72.0 units. If the mass of Object 1 is one-fourth the original value AND the mass of object 2 is tripled AND the distance separating Objects 1 and 2 is halved, then the new gravitational force will be _____ units.

Respuesta :

Answer:

New gravitational force, F' = 216 units

Explanation:

Given that,

Gravitational force between object 1 and 2, F = 72 N

The gravitational force between two objects is given by :

[tex]F=\dfrac{Gm_1m_2}{r^2}[/tex]

[tex]\dfrac{Gm_1m_2}{r^2}=72[/tex]............(1)

If the mass of object 1, [tex]m_1'=\dfrac{m_1}{4}[/tex]

[tex]m_2'=3m_2[/tex]

If the distance between objects is halved, [tex]r'=\dfrac{r}{2}[/tex]

Let new gravitational force is F'. It is changed to :

[tex]F=\dfrac{Gm'_1m'_2}{r'^2}[/tex]

[tex]F'=\dfrac{G\times \dfrac{m_1}{4}\times 3m_2}{(\dfrac{r}{2})^2}[/tex]

[tex]F'=3\times \dfrac{Gm_1m_2}{r^2}[/tex]

[tex]F'=3\times F[/tex]

[tex]F'=3\times 72[/tex]

F' = 216 units

So, the  new gravitational force will be 216 units.