Answer:
New gravitational force, F' = 216 units
Explanation:
Given that,
Gravitational force between object 1 and 2, F = 72 N
The gravitational force between two objects is given by :
[tex]F=\dfrac{Gm_1m_2}{r^2}[/tex]
[tex]\dfrac{Gm_1m_2}{r^2}=72[/tex]............(1)
If the mass of object 1, [tex]m_1'=\dfrac{m_1}{4}[/tex]
[tex]m_2'=3m_2[/tex]
If the distance between objects is halved, [tex]r'=\dfrac{r}{2}[/tex]
Let new gravitational force is F'. It is changed to :
[tex]F=\dfrac{Gm'_1m'_2}{r'^2}[/tex]
[tex]F'=\dfrac{G\times \dfrac{m_1}{4}\times 3m_2}{(\dfrac{r}{2})^2}[/tex]
[tex]F'=3\times \dfrac{Gm_1m_2}{r^2}[/tex]
[tex]F'=3\times F[/tex]
[tex]F'=3\times 72[/tex]
F' = 216 units
So, the new gravitational force will be 216 units.