Answer:
The proof is written below.
Step-by-step explanation:
Given:
[tex]DF \cong EF\\FG\ \textrm {bisects}\ \angle DFE[/tex]
Prove :
[tex]\triangle DFG \cong \triangle EFG[/tex]
Proof:
[tex]DF \cong EF \ \textrm{Given}\\FG\ \textrm{bisects}\ \angle DFE\ \textrm{Given}\\[/tex]
[tex]\angle 1 \cong \angle 2[/tex] Definition of angle bisector
[tex]\overline{FG} \cong \overline{FG}\ \textrm{Reflexive Property}\\\triangle DFG \cong \triangle EFG\ \textrm {SAS Congruence}[/tex]
