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A 1.0-m long wire is carrying a certain amount of current. The wire is placed perpendicular to a magnetic field of strength.20 T. If the wire experiences a force of 0.60 N, what is themagnitude of the current moving through the wire?
A) 1A
B) 5A
C) 4A
D) 2A
E) 3A

Respuesta :

Answer:

Current, I = 3 A

Explanation:

It is given that,

Length of the wire, l = 1 m

Magnetic field acting on the wire, B = 0.2 T

The magnetic force acting on the wire, F = 0.6 N

Let the current flowing through the wire is given by I. The magnetic force acting on an object in the uniform magnetic field is given by :

[tex]F=ILB\ sin\theta[/tex]

Here, [tex]\theta=90^{\circ}[/tex]

[tex]F=ILB[/tex]

[tex]I=\dfrac{F}{LB}[/tex]

[tex]I=\dfrac{0.6\ N}{1\ m\times 0.2\ T}[/tex]

I = 3  A

So, the current flowing through the rod 3 A.

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