Answer:
[tex]8\div9\times3\div16+1\div12=\frac{1}{4}[/tex]
Step-by-step explanation:
Given operation:
[tex]8\div9\times3\div16+1\div12[/tex]
Using PEDMAS to evaluate the order of operations.
First division:
[tex]=\frac{8}{9}\times\frac{3}{16}+\frac{1}{12}[/tex]
Next multiplication:
[tex]=\frac{1}{6}+\frac{1}{12}[/tex]
Then addition:
taking LCD of [tex]6\ and\ 12=12[/tex]
[tex]=\frac{2}{12}+\frac{1}{12}[/tex]
[tex]=\frac{3}{12}[/tex]
reducing to simplest fraction by division of both numbers by GCF.
[tex]=\frac{3\div3}{12\div3}=\frac{1}{4}[/tex]
