Answer:
a) The sign of the charge is positive.
b) The magnetic force on the particle is 0.050 newtons.
Explanation:
The magnetic force F on a moving charge with velocity v passing through a magnetic field B is:
[tex] \overrightarrow{F}=q\overrightarrow{v}\times\overrightarrow{B} [/tex](1)
a)
Because it is a cross product, we can find the direction of the force using the right-hand rule, that is too the direction of the movement. We have two possibilities here because the velocity vector and magnetic field are perpendicular: the particle deflects towards east or toward west, which depends on the charge of the particle. Note that if you put your right hand fingers, except thumb, pointing towards north (direction of velocity) and later close them in the direction of the magnetic field, if you maintain your thumb perpendicular to this movement it will point towards east (See figure), so that will be de direction of the force if the charge is positive, but if the charge is negative, the direction will be opposite (towards west). So the charge has to be positive to deflects towards east.
b)
Now by 1:
[tex] F=qvB\sin\theta=(8.50\times10^{-6})(4750)(1.25)\sin90\simeq\mathbf{0.050\,N} [/tex]
Sign of the charge of this particle is positive deflected towards the east and magnitude of the magnetic force of particle is 0.050 N.
The magnetic field is the field in the space and around the magnet in which the magnetic field can be fill.
Magnetic force is the force of attraction of repulsion between two poles of the two magnets. The magnetic force is also appears between two electrically charged bodies.
The magnetic force in the vector form can be given as,
[tex]F=qvB\sin\theta[/tex]
Here, (q) is the charge, (B) is the strength of the magnetic field, and (v) is the velocity ([tex]\theta[/tex]) is the angle between the direction of vectors.
Here, the particle initially moving northward and deflected toward the east. By the Fleming's left hand rule,the direction of its velocity must be in south direction.
The magnetic filed of it should act in downward with the plane. Therefore the sign of the charge of the particle should be positive.
The value of magnetic field which is directed vertically upward is 1.25 T.
The particle having a charge of magnitude 8.50μC and initially moving northward at 4.75 km/s is deflected toward the east.Thus, put the values in the above formula as,
[tex]F=(8.50\times10^{-6}\times4650\times1.25)\sin(90)\\F=0.050\rm N[/tex]
Thus, the sign of the charge of this particle is positive deflected towards the east and magnitude of the magnetic force of particle is 0.050 N.
Learn more about magnetic field here;
https://brainly.com/question/7802337
