Suppose you have a date with your spouse. There are 5 movies you can choose to watch together: 1 drama, 2 action, and 2 comedy. For dinner, you can have 2 types of noodles, 3 types of salads, or 2 types of meat. What is the probability, assuming choosing dinner and a movie are independent events, that you choose a drama and have noodles for dinner? Round to the nearest thousandths.

Question

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Respuesta :

nemeka nemeka · Answer 1 · 2019-11-24T13:22:57+01:00

Answer:

0.4857

Explanation:

probality=no of possible events/total no of outcomes.

Here,no of movies=5

no of noodles=2

no of salads =3

or meat=2

So or here denotes multiplication

Therefore total for number of salads or meat is-3+2=5

From the statement,choosing a dinner and movie are independent events.

So prob of drama is 1/5(1 drama in total no of 5movies of drama,action&comedy)

Also,prob of noodles is 2/7(2noodles in total no of 7 of noodles,salad&meat)

Therefore the probalitity of choosing dinner and a movie is =1/5*2/7=0.4857

laurencewei laurencewei · Answer 2 · 2020-04-28T21:46:10+02:00

Answer:

.057

Explanation:

The probability of choosing a drama is

1/5

The probability of having noodles for dinner is

2/7

Therefore, the probability that you choose a drama and have noodles for dinner is

1/5⋅2/7=2/35=0.057

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