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A 96.1 kg man sits on the stern of a 6 m long boat. The prow of the boat touches the pier, but the boat isn’t tied. The man notices his mistake, stands up and walks to the boat’s prow, but by the time he reaches the prow, it’s moved 3.66 m away from the pier. Assuming no water resistance to the boat’s motion, calculate the boat’s mass (not counting the man). Answer in units of kg.

Respuesta :

Info:

weight: 96.1 kg

Length: 6 m

moved: 3.66 m

Answer:

m L = m d + M d

m L − m d = M d

m (L − x) = M x

M = m (L − x) / x

M = 96.1 kg (6 m − 3.66 m) / 3.66 m

M =  61.44098361 kg

The boats mass.

A 96.1 kg of man sits on a stem of a 6-meter longboat. The boat ouches the pier and but is not tied. The man notices a mistake and walks to the prow of the boat he moves a distance of 3.66 meters away from the pier. Thus assuming the given information the bot offers no resistance.

The mass of the boat will be equal to 61.4 kg.

  • As all the given information states that the boat is not tied and is at a distance f 3.66 m. The mass of boat will be  m L = m d + M d
  • m L − m d = M d  m (L − x) = M x
  • M = m (L − x) / x    then the M = 96.1 kg (6 m − 3.66 m) / 3.66 m
  • Hence the M =  61.44098361 kg.

Learn more about the man sits on the stern.

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