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When sodium metal is added to water, the following reaction occurs:
2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)
What is the theoretical number of moles of hydrogen gas should be produced when 0.068 mol of sodium metal reacts?
a. 1.0 mol H2
b. 0.14 mol H2
c. 0.068 mol H2
d. 0.034 mol H2

Respuesta :

Answer:

d. n H2(g) = 0.034 mol

Explanation:

  • 2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)

                              2 - Na - 2

                              4 - H - 4

                               2 - O - 2

∴ n Na(s) = 0.068 mol

⇒ n H2(g) = ( 0.068 mol Na(s) )( mol H2(g) / 2 mol Na(s) )

⇒ n H2(g) = 0.034 mol